36x^2-432x+720=0

Solution for 36x^2-432x+720=0 equation:

36x^2-432x+720=0

a = 36; b = -432; c = +720;
Δ = b2-4ac
Δ = -4322-4·36·720
Δ = 82944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{82944}=288$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-432)-288}{2*36}=\frac{144}{72}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-432)+288}{2*36}=\frac{720}{72}
=10
$